## Linear Operators, Part 2 |

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Page 861

If T

If T

**exists**in B ( X ) , then Te [ ( T ; ' y ) z ] = yz , ( T ? ' y ) 2 = 7 ' ( yz ) , and if a = Tole , then az = Tilz for every ze X. Also xa = T a = e = T : ' ( Te ) = T ; ' ( ex ) = ( T7'e ) x Thus x - l**exists**and T ; lz = x - 1z .Page 1057

Thus , to complete the proof of the present lemma , it suffices to show that Ω ( y ) 2 ( y ) ( 3 ) f ( x ) = So eiyu dy odos twise ly " eiyu dy En lyn R - 00

Thus , to complete the proof of the present lemma , it suffices to show that Ω ( y ) 2 ( y ) ( 3 ) f ( x ) = So eiyu dy odos twise ly " eiyu dy En lyn R - 00

**exists**for each u . By Lemma 2 , the integral 0 ( tu )**exists**...Page 1261

23 If an operator T has a closed linear extension there

23 If an operator T has a closed linear extension there

**exists**a unique closed linear extension T such that if T , is any closed linear extension of T then T CT , T is called the closure of T. ( a ) There**exists**a densely defined ...### What people are saying - Write a review

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### Contents

BAlgebras | 859 |

Bounded Normal Operators in Hilbert Space | 887 |

Miscellaneous Applications | 937 |

Copyright | |

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