 | Charles Hutton - 1807 - 464 Seiten
...find the Area of any Parallelogram ,- "whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area*. EXAMPLES. * The truth of this rule is proved in the Geom. theor. 81, cor. 2. The same is otherwise... | |
 | Charles Hutton - 1811 - 494 Seiten
...fold the Area of any Parallelogram ; whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area *. EXAMPLES. * The truth of this rule is proved in the Geom. theor. 81, cor. 2. The same is otherwise... | |
 | George Fisher (accountant.) - 1811 - 302 Seiten
...Circumference. Rule. Multiply the Number 0,0/06775 (or in common, 0,0790) by the Square of the Circumference, the Product will be the Area. Example. What is the Area of a Circle whose Circumference is 34^ Inches ? £4,5 1190,25 34,5 0,0796 714150 1380 1071225 K)35 833175... | |
 | 1816 - 764 Seiten
...parallelogram, whether it be a fquare, a rectangle, a rhombus or a rhomboid. Fig. 13, 14, 15, 17. RULE i. Multiply the length by the perpendicular breadth, or height, and the product will be the area. If two fides and an included angle of a parallelogram are given to find the area, thcn make ufe i>:... | |
 | Charles Hutton - 1818 - 646 Seiten
...Area of any Parallelogram ; whether it be a Square, a Rectanglt, a Rhombus, or a Rlwmboid. MULT1PLY the length by the perpendicular breadth, or height, and the product will be the area*. EXAMPLES. • The truth cf this rule is proved in the Oom. theor. 81, cor. .2The smie is otherwise... | |
 | Charles Hutton - 1822 - 616 Seiten
...find Ike Area, of any Parallelogram ; whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area.* EXAMPLES * The truth of this rule is proved in the Geom. thcor. 81, cor. 2. The same, is otherwise... | |
 | Beriah Stevens - 1822 - 436 Seiten
...the area, without the help of the diameter. RULE. Mulliplv the square of the circumference by ,07958, and the product will be the area. EXAMPLE. What is the area of a circle whose circumference is 44 1 44 X44 X ,07958, = 1 54,06608, answer. PROBLEM 16lh. The area of... | |
 | Charles Hutton - 1825 - 608 Seiten
...of any Parallelogram ; whether it be a Square, a Rectanglt, a Rhombus, or a Rhomboid. MULTIPLY tbe length by the perpendicular breadth, or height, and the product will be t^e area.* EXAMPLES * The trulli of this rule is proved in the Oeom. theor. 81, cor. 2. The same is... | |
 | Thomas Curtis - 1829 - 810 Seiten
...PROBLEM I. To find the area of a parallelogram. Rule 1.— Multiply the length by the perpendicular height, and the product will be the area. Example. — What is the area of a rhombus whose side is 12-24 feet, and height 9'16 feet? 12-24 x 9-16= 112-1184 feet. Answer. Rule 2.... | |
 | Ira Wanzer - 1831 - 408 Seiten
...To find the area of any Parallelogram' whether it be an Oblong, a Square, a Rhomboid, or a Rhombus. RULE.— Multiply the length by the perpendicular...breadth, or height, and the product will be the area. Note 1 . — Since the length and breadth of a square are equal, the area* is evidently equal to the... | |
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PROBLEM I. To find the Area of any Parallelogram ,- "whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area*. 
