The Speaker: Or, Miscellaneous Pieces, Selected from the Best English Writers, and Disposed Under Proper Heads, with a View to Facilitate the Improvement of Youth in Reading and SpeakingJ. Johnson, 1792 - 436 Seiten |
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Ergebnisse 1-5 von 33
Seite 3
... equals are added to equals , the result are equal , ( b ) when equals are multiplied by equals , the results are equal , ( c ) when the same is added to equals , the results are equal , ( d ) when the same is multiplied by equals , the ...
... equals are added to equals , the result are equal , ( b ) when equals are multiplied by equals , the results are equal , ( c ) when the same is added to equals , the results are equal , ( d ) when the same is multiplied by equals , the ...
Seite 1056
... equal to 40 cc . of 0.02 N was taken in a 500 cc . Erlenmeyer , an aliquot of cyanide equal to 0.02 g . CN added , then 50 cc . of halide - free sodium hydroxide , which was equal to 0.8 g . of sodium . Each solution was diluted to ...
... equal to 40 cc . of 0.02 N was taken in a 500 cc . Erlenmeyer , an aliquot of cyanide equal to 0.02 g . CN added , then 50 cc . of halide - free sodium hydroxide , which was equal to 0.8 g . of sodium . Each solution was diluted to ...
Seite 36
... equal angle by first looking for the sides which are given equal . A M is given equal to B N , and the angles opposite these equal sides are equal ; .. in As A D M and BCN at D Zat C. Also A D was proved equal to B C ; hence the angles ...
... equal angle by first looking for the sides which are given equal . A M is given equal to B N , and the angles opposite these equal sides are equal ; .. in As A D M and BCN at D Zat C. Also A D was proved equal to B C ; hence the angles ...
Seite 63
... equal to a given rectangle , and have the sum of the squares of the sides equal to a given square , and the difference of the segments of the base made by the perpendicular from the vertical angle a given difference . Solution by R ...
... equal to a given rectangle , and have the sum of the squares of the sides equal to a given square , and the difference of the segments of the base made by the perpendicular from the vertical angle a given difference . Solution by R ...
Seite 56
... equal to the large original one . But when this occurs all the small semicircumferences coincide with the diameter of the circle and their sum is hence equal to it . Accordingly , it has been proved that the semicircumference of any ...
... equal to the large original one . But when this occurs all the small semicircumferences coincide with the diameter of the circle and their sum is hence equal to it . Accordingly , it has been proved that the semicircumference of any ...
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